这里与大家分享一个替换文件中某字符串的小程序，经测试完全可用，希望对大家有帮助

import java.io.BufferedReader;

import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.IOException; import java.io.InputStreamReader; import java.io.PrintWriter;

public class ReplaceWordUtil {

 public static void main(String[] args) {   /**    * arg0 文件路径    * arg1 需要替换的内容    * arg2 新内容    */   iteratorDirectory("d:/test","","");  }

 public static void iteratorDirectory(String filepath,String oldStr,String replaceStr) {

  File file = new File(filepath);   if (file.isDirectory()) {    String[] fileList =  file.list();        for(int i=0;i<fileList.length;i++) {     iteratorDirectory(filepath+"\\"+fileList[i],oldStr,replaceStr);    }   }else {    replaceTxtByStr(filepath,oldStr,replaceStr);   }  }   public static void replaceTxtByStr(String path,String oldStr,String replaceStr) {          String temp = "";          int len = oldStr.length();          StringBuffer tempBuf = new StringBuffer();          try {              File file = new File(path);              FileInputStream fis = new FileInputStream(file);              InputStreamReader isr = new InputStreamReader(fis);              BufferedReader br = new BufferedReader(isr);              StringBuffer buf = new StringBuffer();                          while((temp = br.readLine()) != null) {               if(temp.contains(oldStr)) {                int index = temp.indexOf(oldStr);                tempBuf.append(temp);                tempBuf.replace(index, index+len, replaceStr);                buf.append(tempBuf);                tempBuf.setLength(0);               }else {                buf.append(temp);               }                buf = buf.append(System.getProperty("line.separator"));                             }              br.close();              FileOutputStream fos = new FileOutputStream(file);              PrintWriter pw = new PrintWriter(fos);              pw.write(buf.toString().toCharArray());              pw.flush();              pw.close();          } catch (IOException e) {              e.printStackTrace();          }      }

}